Concatenation of permutations

Concatenate words or cycles together

Usage

# S3 method for class 'word'
c(...)
# S3 method for class 'cycle'
c(...)
# S3 method for class 'permutation'
rep(x, ...)

Arguments

...

In the methods for c(), objects to be concatenated, which all must be of the same type: either all word, or all cycle

x

In the method for rep(), a permutation object

Author

Robin K. S. Hankin

Note

The methods for c() do not attempt to detect which type (word or cycle) you want as conversion is expensive.

Function rep.permutation() behaves like base::rep() and takes the same arguments, eg times and each.

See also

size

Examples

x <- as.cycle(1:5)
y <- cycle(list(list(1:4,8:9), list(1:2)))


# concatenate cycles:
c(x,y)
#> [1] (12345)    (1234)(89) (12)      

# concatenate words:
c(rperm(5,3),rperm(6,9))   # size adjusted to maximum size of args
#>  [1] (13)         (23)         (23)         ()           (23)        
#>  [6] (148935267)  (14395)(278) (174629538)  (146275398)  (168975)(34)
#> [11] (2384)(596) 
#> [coerced from word form]


# repeat words:
rep(x, times=3)
#> [1] (12345) (12345) (12345)

# c(id, rperm())  # fails: elements are of different types, one cycle, one word.
c(as.word(id), rperm())   # works: coerce id [which is a cycle] to word form
#>  [1] ()         (142)(576) (1247)(36) (2345)(67) (124753)   (173256)  
#>  [7] (15637)    (1576324)  (12)(57)   (254)(367) (172456)  
#> [coerced from word form]
c(id, as.cycle(rperm()))  # works: coerce rperm() [which is a word] to cycle form
#>  [1] ()          (17436)     (1472)(365) (126)(3547) (17)(465)   (1456327)  
#>  [7] (1367452)   (254736)    (12643)(57) (1437256)   (1725)(364)